VM - Scalar Multiplication Lesson

Scalar Multiplication

Scalar multiplication just means to multiply a matrix by a constant.

For instance, let  LaTeX: A=\begin{bmatrix}
1 & -2 & 5\\
0 & 4 & -1
\end{bmatrix}A=[125041] then if we want to find 2A, we would multiply each entry by 2.

So,  LaTeX: 2A=\begin{bmatrix}
2 & -4 & 10\\
0 & 8 & -2
\end{bmatrix}2A=[2410082]

Try a few problems to see if you've got it:

LaTeX: A=\begin{bmatrix}
-4 & 7 & 9\\
0 & 3 & 2
\end{bmatrix}
B=
\begin{bmatrix}
3 & 6 & 8\\
-1 & -2 & 0
\end{bmatrix}
C=\begin{bmatrix}
1 & 0 & 5\\
4 & 2 & -2\\
7 & -3 & 1
\end{bmatrix}
D=
\begin{bmatrix}
7 & -2 & 0\\
5 & 3 & 3\\
6 & -1 & 4
\end{bmatrix}A=[479032]B=[368120]C=[105422731]D=[720533614]

Try these problems to see if you get the correct solution.

  1. Problem: -3B
  • Solution: LaTeX: -3B=\begin{bmatrix}
-9& -18 & -24\\
3 & 6 & 0
\end{bmatrix}3B=[91824360]
  1. Problem: (1/2)C
  • Solution: LaTeX: \frac{1}{2}C=\begin{bmatrix}
\frac{1}{2}& 0 & \frac{5}{2}\\
2 & 1 & -1\\
\frac{7}{2} & -\frac{3}{2} & \frac{1}{2}
\end{bmatrix}12C=[12052211723212]
  1. Problem: 3C+2D
  • Solution: LaTeX: 3C+2D=\begin{bmatrix}
17& -4 & 15\\
22 & 12 & 0 \\
33 & -11 & 11
\end{bmatrix}3C+2D=[1741522120331111]
  1. Problem: 4B - A
  • Solution: LaTeX: 4B-A=\begin{bmatrix}
16 & 17 & 23\\
-4 & -11 & -2
\end{bmatrix}4BA=[1617234112]

Application:

The revenue generated by sales in the Vancouver and Quebec branches of the A-Plus auto parts store was as follows:

Revenue generated by sales in the Vancouver and Quebec branches of the A-Plus auto parts store
Vancouver Quebec
Wiper Blades 140 150
Clean Fluid (bottles) 30 36
Floor Mats 96 48

If the Canadian dollar was worth $0.65 U.S. at the time, compute the revenue in U.S. dollars.

We need to multiply each revenue figure by 0.65. Let A be the matrix of revenue figures in Canadian dollars:

table matrix

The revenue figures in U.S. dollars are then given by the scalar multiple

scalar multiple example

In other words, in U.S. dollars, $91 worth of wiper blades was sold in Vancouver, $68.25 worth of wiper blades was sold in Quebec, and so on.

Another example:

The A-Plus auto parts store had the following sales in its Vancouver store:

Vancouver Store Sales
Vancouver
Wiper Blades 20
Clean Fluid (bottles) 10
Floor Mats 8

We need to multiply each sales figure by the corresponding price and then add the resulting revenue figures. We represent the sales by a column vector, as suggested by the table.

q matrix

We put the selling prices in a row vector.

p matrix

We can now compute the total revenue as the product

Total revenue

So, the sale of these items generated a total revenue of $266.00.

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