MLRF - Proportional Relationships Lesson
Proportional Relationships
Previously you learned to compute unit rates, and use this to compare relationships. We will extend this learning to include identifying and calculating the unit rates and using this information to compare the proportional relationships using graphs, equations, and tables.
Proportional relationships are relationships between two variables where the ratios are always equivalent. This means that both values increase or decrease at the same ratio.
Proportional relationships can be represented using various models, including graphs, tables, and equations. If the ratio between one quantity and another is constant, you can use tables, graphs, and equations of the form y = mx (y = kx) to represent a proportional relationship between the quantities.
Let's look at an example:
John's dad owns a car dealership. John helps out by washing cars on Saturdays. John earns $10 in iTunes gift cards for every 2 cars he washes. So, the proportion of gift cards earned to the number of cars washed is 10 to 2. Of course, we can reduce that to 5 to 1.
The amount in gift cards earned for x number of cars washed can be represented by a line. The slope of that line is the proportion represented by the above ratio, which written as a fraction is 5/1, or 5, and the y-intercept is zero.
We can represent this with the following equation: y = 5x
A graph of this equation is shown below.
Rate of change, constant of proportionality, and slope can be used synonymously, and the rate of change is determined by the change in the y values divided by the change in the x values. This is represented by the slope formula: :
m=y2−y1x2−x1
So, what is our unit rate on this example? Let's pick two points and use the definition of rate of change to determine the rate of change. We'll use the points (0, 0) and (5, 1); however, any two points on the line will yield the same result since it is a linear function, i.e., a line.
m=y2−y1x2−x15=01−0515
Therefore, the rate per gift card amount is $5 per car washed.
We could have also stated that since we know we are looking for unit rate, we can use the formula y=kx which shows k as the constant of proportionality. To solve for k, the constant of proportionality, or the unit rate, we can say k = y/x = 10/2 = 5. Either way, the unit 5, or slope is $5/car.
As we have seen in the above discussion and example, a proportional relationship can be represented by the equation y = mx where m is the slope or rate of change. Remember on these examples our y-intercept is zero, which means the line passes through the origin.
We can compare the rates of change between equations. The equation with the greater value of m, or slope, will have the greater rate of change.
Example:
Compare the rates of change of the following equation and table. Determine which has the greater rate of change.y=12x
x |
y |
---|---|
0 |
0 |
4 |
3 |
8 |
6 |
12 |
9 |
First, examine the slope, or rate of change, for the graph and for the table separately. Then, compare the two slopes to determine which is larger.
For the equation, y=12x, the rate of change can be pulled directly from the equation. Because it is already in slope-intercept form, y = mx + b, we can see directly that the coefficient of x, labeled as m, is the slope, or rate of change, of the equation.
Therefore, the rate of change for the equation is ½.
Now, let's take a look at the table. Here, it is easiest to use the formula for finding the rate of change. The formula m=y2−y1x2−x1 tells us how to find slope. We can pick any two points from the table and substitute them into this formula.
(4, 3) and (12, 9) will be the points we'll substitute into the formula.
m=y2−y1x2−x1m=9−312−4m=68m=34
Therefore, the rate of change of the table is ¾. Please keep in mind that we would have gotten ¾ for any two points chosen.
Since ¾ > ½, the rate of change of the table is greater than that of the equation.
Notice that we can use any two points to determine the slope of the line defined by the points in the table. Why is this?
The slope of a line is the same between any two pairs of points on the line. This can be demonstrated using similar triangles.
Proportional Relationships Practice
If you would like to practice more problems and check your work, click Here. Links to an external site. Make sure you check your answers and look at the course resources or ask your teacher if there are any problems you do not understand. Links to an external site.
IMAGES CREATED BY GAVS