ISPA - Integral and Comparison Tests
Integral and Comparison Tests
In the previous lesson the terms of the infinite series were any real numbers, positive, negative, or zero. For purposes of the Integral Test, Comparison Test, and Limit Comparison Test, only terms that are nonnegative numbers will be considered. The rationale for this restriction is that the partial sums of such series form nondecreasing sequences, and nondecreasing sequences that are bounded from above always converge.
Series Terms as Areas of Rectangles and Relationship to Improper Integrals
Think of the terms of a positive series as rectangular areas with each base of length 1 and heights of a1 , a2 , a3 , ... . For example, consider the harmonic series ∑∞n=11n and compare it to its corresponding integral
∫∞11xdx as illustrated in the graph.
The respective areas represent the total "left-hand" rectangular areas from 1 to . The area under the curve of the function y = 1/x is less than the total area of the rectangles, or written another way, the integral
∫∞11xdx≤a1+22+a3+... . This improper integral is known to diverge, i.e., the area under the curve is infinite. So the sum of the series
∑∞n=11n must also be infinite and the series is divergent. In general, the series
∑∞n=1an and its related integral
∫∞1a(x)dx either both converge or both diverge.
Integral Test
Unlike many of the series previously discussed, it is generally difficult to find an expression for sn, the nth partial sum, that is simple enough to decide whether or not it possesses a limit as n→∞. Determining whether a series is convergent or divergent without explicitly finding its sum can be accomplished using a test involving improper integrals.
The Integral Test states that if f is a continuous, positive, decreasing function on
[1,∞)andan=f(n), then the series
∑∞n=1an and the integral
∫∞1a(x)dx both converge or both diverge. The next presentation illustrates using the Integral Test on the harmonic series and two other series.
Examples of using the Integral Test to determine convergence or divergence of a series follow.
The Integral Test applied to other series is depicted in the next presentation.
Convergence and Divergence of the p-Series
The p-series is a generalization of the harmonic series where ∑∞n=11nP=11P+12P+13P+.... It would be helpful to know for which values of p the series converges. If p < 0, then
limn→∞1nP=∞. If p = 0, then
limn→∞1nP=1. In either case
limn→∞1nP≠0, so the given series diverges by the nth Term Test for Divergence. If p > 0, then the function f(x) = 1/xp is continuous, positive, and decreasing on
[1,∞). Recall from the Integration Techniques, L'Hopital's Rule, and Improper Integrals module that
∫∞1dxxP diverges if p < 1 and converges if p > 1. Then by the Integral Test, the series converges if p > 1 and diverges if 0 < p < 1. (Note that when p = 1, this p-series is the harmonic series.) These conclusions form the basis of the p-Series Test, which states that the p-series
∑∞n=11nP is convergent if p > 1 and divergent if p < 1. Consider the p-series
1+13√2+13√3+...=1+1213+1313+.... Since p = 1/3 and
p≤1, then the series diverges by the p-Series Test. The next presentation focuses on using the p-Series Test to determine convergence or divergence.
Comparison Tests
Comparison tests do not require finding an expression for the nth term partial sum. Just as the Integral Test compared an infinite series with a related improper integral, comparison tests compare a given series with a series that is known to be convergent or divergent.
Comparison Tests (Direct Comparison Test)
The Comparison Test is sometimes referred to as the Direct Comparison Test, which is more descriptive of what actually occurs. The Comparison Test states the following:
Suppose that ∑anand∑bn are series with positive terms.
i) If ∑bn is convergent and an < bn for all n, then
∑an is also convergent.
ii) If ∑bn is divergent and an > bn for all n, then
∑an is also divergent.
View the presentation below describing the Comparison Test and illustrating its application to three examples.
To explore the Comparison Test using an interactive applet, CLICK HERE. Links to an external site.
Limit Comparison Test
The next test is particularly useful with series in which an is a rational function of n. The Limit Comparison Test states: Suppose ∑anand∑bn are series with positive terms. If
limn→∞anbn=c, where c is a finite number and c > 0, then either both series converge or both diverge.
View the presentation below illustrating the Limit Comparison Test.
The presentation below includes examples of using both the Limit Comparison Test and the Comparison Test.
Integral and Comparison Tests Practice
PROBLEM: Emily uses the integral test to determine if ∑∞k=13k2 converges. She finds that
∫∞13x2dx=3. She then states that
∑∞k=13k2 converges and the sum is 3. What error did she make?
SOLUTION: Emily is correct that the series converges. Her error was saying that the value of the related integral gives the sum of the infinite series. ∑∞k=13k2=3+34+39+... is greater than 3.
Integral and Comparison Tests: Even More Problems!
Complete problems from your textbook and/or online resources as needed to ensure your complete understanding of differential equations and general and particular solutions.
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